WebbAnswer (1 of 4): 360n = (2^3)(3^2)5n = (3^3)(5^2)m where “n" and “m" are not integers but positive integers. (2^3)n = (3)(5)m <=> 360n = 675m or 8n = 15m. No positive integers m exists such that 8(n = 1, 2, 3 … 14) = 15m. The smallest n: 8(15) = (15)(8). n = 15 and m = 8. n = 15 is the small... Webb20 juni 2016 · Find the smallest positive integer which can be written as the sum of the squares of two positive integers in two different ways. I took extremely long to solve this . I got . $50= 7^2 + 1^2 $ ... 39.1k 5 5 gold badges 43 43 silver badges 84 84 bronze badges $\endgroup$ Add a comment 0
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Webb11 n = 2 x + 1. This is equivalent to. x = 11 n − 1 2. Note here that for x to be an interger we need 11 n − 1 to be even. This happens exactly when n is odd. And when n = 2 m + 1 is odd, then. x = 22 m + 11 − 1 2 = 11 m + 5. So the solution is all those integers x of the form 11 m + 5 where m is any integer. For the second one, you do ... WebbPrime Factorisation of 84. 84 is a composite number, so the prime factors of 84 can be found using the below steps. The first step is to divide the number 84 with the smallest prime factor, i.e. 2. 84 ÷ 2 = 42. Again, divide 42 by 2. 42 ÷ 2 = 21. Now, if we divide 21 by 2 we get a fraction number, which cannot be a factor.
Webb16 aug. 2015 · The smallest possible number is 4. Pop the number (i.e. the front element of the queue) and push the numbers that can be derived from this popped number. That is , … Webb12 apr. 2024 · As the integers are consecutive we could let them be: x,x +1 and x + 2. Their sum is 84. x + x + 1 + x + 2 = 84. 3x +3 = 84. 3x = 81. x = 27. This is the smallest of the …
WebbIn mathematics, the least common multiple, also known as the lowest common multiple of two (or more) integers a and b, is the smallest positive integer that is divisible by both. It … Webb12 apr. 2024 · Their sum is 84 x + x + 1 + x + 2 = 84 3x +3 = 84 3x = 81 x = 27 This is the smallest of the integers which are: 27,28,29 Answer link Rhys Apr 12, 2024 27,28 and 29 Explanation: Let the first be n, and if they are consecutive then the next two numbers are n +1 and n + 2 The sum means addition: n + (n + 1) +(n +2) = 84 Collect like terms: 3n +3 = …
Webb1 aug. 2024 · For each of n = 84 and n = 88, find the smallest integer multiple of n whose base 10 representation consists entirely of 6's and 7's. modular-arithmetic 1,208 $n=84:$ …
Webb21 jan. 2016 · To solve this, you represent the the question as: x+ (x+1)+ (x+2)=84 Three consecutive integers can be represented as x, x+1, x+2. If those three integers sum to … swiss tariffWebb6 maj 2024 · Use min () to get the smallest number numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, -1] min (numbers) #-1 Use max () to get the largest number max (numbers) #9 You can use mean () to get the average of a list from statistics import mean mean (numbers) #4 Share Improve this answer Follow answered May 6, 2024 at 3:34 PacketLoss 5,481 1 8 27 Add … swiss tarotWebb21 jan. 2016 · 1 Answer Ed Hitchcock Jan 21, 2016 To solve this, you represent the the question as: x + (x + 1) +(x +2) = 84 Explanation: Three consecutive integers can be represented as x,x +1,x +2. If those three integers sum to 84, then x + (x + 1) +(x +2) = 84 and then we simplify x + x + 1 + x + 2 = 84 3x +3 = 84 3x = 84− 3 x = 81 3 = 27 so x = 27 x … swiss tartanWebb26 dec. 2024 · The video uses x as the smallest integer, and x + 2 as the largest. This way, we can simply solve for x and find the smallest integer. If we use x, x - 1, x - 2, then x is our greatest integer, and x - 2 is our smallest. So we have to solve for x first, and then subtract 2 from it to find the value of quantity A. swiss tarot major arcanaswiss task forceWebb36 rader · The integer 84 is an even number. The integer 84 is a Composite number. 140 is greater than 84, so 84 is an abundant number. swiss tattooWebbIn arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by lcm (a, b), is the smallest positive integer that is divisible by both a and b. swiss tarts recipe